Dear Professors and fellow colleagues please this may be an easy one but Please kindly assist as i have been pondering on it over days.

I am working with biochar in a Pot experiment with 2kg of soil (pot height 17cm and diameter 18cm) from my understanding i calculated the rate of biochar based on field rate as for example

Calculating procedure

Height of pot = 15cm

Density of soil = 1.2g/cm3

Area= 1ha = 10000 m2 =100,000,000 cm2

M = p x V

M top soil = 1.2g cm3 × (1.5 cm x 108 cm2)cm3

=1.8×109 g = 1.8×106kg

Biochar at 5MT = (5 MT ×〖10〗^6 g/MT)/(1.8× 〖10〗^6 kg)= 2.778 g/kg

M (biochar per pot) = M soil per pot x Dosage = 2 x 2.778 = 5.556 g

But in all the papers i read i see something like this ... Six application

rates of 0%, 0.3%, 0.8%, 1.7%, 2.8%, 3.3% (kg of biochar per kg of soil) where tested in a fully randomized experimental design with three

replicates. The biochar doses were equivalent to application rates of 0, 10, 30, 60, 100 and 120 t biochar ha-1

Please my question is does applying biochar at the rates(0%, 0.3%, 0.8%, 1.7%, 2.8%, 3.3%) imply for example referring to my calculation above if 5Mt is being applied at 8% does it imply after my calculation i find 8% of my answer 5.448 g/kg which is 0.44448 or my calculation is right and i am just over thinking this

Please Thank You