The atmospheric sampling was done in quartz fibre filter paper .Then the sample paper was digested and volumed upto 100mL and further analysed in ICP-MS for metals.
To convert ICP-MS data from micrograms per liter (µg/L) to micrograms per cubic meter (µg/m³), you can use the following relationship:
1. the conversion factors:
1 liter (L) is equivalent to 0.001 cubic meters (m³).
Therefore, to convert from µg/L to µg/m³, you need to account for the volume conversion.To convert ICP-MS data from µg/L to µg/m³, multiply the concentration in µg/L by 1000. For example, 50 µg/L converts to 50000 µg/m³.
You are collecting the metals on the filter paper by running air through it using a pump I believe. Therefore the final value should be µg/m3 of air that was sampled.
So calculate the µg s of the analyte in the 100 mL digested solution.
If the ICP-MS result is X µg/L, this value would be 0.1X µg.
Now divide this number by the m3 of air sampled, to get the µg/m3 final result. You have to calculate the air volume from the flow rate and the sampling time used during atmospheric sampling.
Angelo Ransirimal Fernando if a portion (lets's say 1/4th) of the sampled filter paper was digested to analyzed in ICP-MS, then how do I correlate the matter with the calculation above?