Dear Researchers, anybody answer me how much of water will be added to obtain 16% moisture in 100 g of mix flours of Corn (6.5% moisture) and Rice (5% moisture) in 3:1 (mixture ratio) respectively and how to calculate?
in 3:1 ratio corn contains 4.9g and rice1.3g moistur (mixture contains average 6.2% moisture) remaining 16-4.9-1.3=.9.8 water to be added to get 16% moiture
Thank you so much sir......but then we have to measure water in gram.
Thank you Amit Kumar Mukherjee Sir, I think this is more accurate..thanks
on a basis 100 g we can say that the mixture contain 75 g corn flour and 25 g rice flour. Suppose the water have to added is w, then the material balance for moisture is mass of moisture originally present + mass of water added = Final mass of moisture
(mass of moisture in corn flour) + (mass of moisture in rice flour) + mass of water added = final mass of moisture
(75 x 0.065) + (25 x 0.05) + w = 6.125 w
Mass of Final moisture divided by mass of ( flour mixture + water added) = 0.16
(6.125 +w)/ (100+w) = (16/100)
612.5 +100 w = 1600 + 16 w
w = 11.76 g
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