Hello. I just downloaded monthly mean wind speed data from ERA-interim with time range of 2007 to 2015 and spatial resolution of 1°×1° in NetCDF type. Because I already have some other remote sensing data in 1°×1° grid, I chose 1°×1° instead of 0.7°×0.7°.
I used the data of global wind speed. I opened the data in MATLAB. And I found the latitude variable has 181 values (go from 90 to -90, including zero) while the longitude variable has 360 values (go from 180 to -179, including zeros). So for every month, the wind speed variable is a matrix of 181*360 grids. But I thought it should be 180*360 grids for global map. So, why did the latitude have one more row? I don't know exactly how I can match the wind speed to my other data (like 1°×1° precipitation, temperature or so of 180*360 grids).
Does anyone have used ERA-interim data and can help me.
Thanks a lot.
181 x 360 is how many positions there are on the surface of the earth with integer coordinates (north and south pole having 360 each) in degrees.
Equator plus 90 degrees in each direction gives you 181.
Longitude is different, since +180 and -180 are the same and one is omitted.
Re: Olof Dahlberg
Thanks so much. I think the each value denotes that of each integer coordinate, I mean, each point of lat/lon. At first I just thought it should represent the value of one 1°×1°. And I think I could interpolate to get a 180x360 data.
Re: Bo Huang
Thanks so much.
I think I need to make interpolation. but may I know what does CDO refer to? I am not familiar with it?~~and how I can make it ?
Re： Lei Zhang
多谢磊哥哈。对的，我一开始以为是一个网格里的值，后来发现只是每个经纬度交点上的值，估计如果要得到网格值需要做一下插值哈。~~
ERA-interim 数据本身不就是栅格值吗？ 栅格的值不是经纬度交点上的值吧？
你可以用ARCGIS里面的Multidimension Tools-->Make NetCDF raster layer打开netCDF文件生成raster
(ps: 我现在使用的是MERRA)
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