According to metcalf and eddy, SRT= working volume * MLSS in reactor/(volumetric flowrate* MLSS of sludge return+ volumetric flow rate *MLSS of clarifier effluent).
But for SBR sludge return is zero. It will contain only the MLSS and volume of decant (50% of working volume). But if the growth is less and settling process brings the sludge level below the 50% of working volume, would the SRT be very large?
How does sludge wastage can control the SRT?. Would decanting itself maintains the SRT? How does letting SRT to vary affects SBR?
Hello
I am also in the same problem, your questions are interesting, thank you for sharing the answers if you have found them elsewhere (@Jayakrishnan.U)
1) The Sludge wastage controls the MLSS in the Reactor.
2) Proper decanting in SBR has a negligible effect on SRT
3) Changing the SRT will reduce or increase the Biomass present in the SBR i.e. treatment efficiency of the SBR.
Thank you very much for your clarification, I do a landfill leachate treatment with RBS, with a total volume of mixed liquor of 1.6 l, is it important in my case to control the TRS? Sameer Kumar Dohare
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