In Abaqus, for an axisymmetric model, when I apply a concentrated force at a point, is this force automatically distributed around the entire circumference corresponding to that radial distance? In other words, does Abaqus treat the concentrated force as a total force applied over the full 360 degrees, effectively making it a line load with intensity F/(2πr), where r is the radial distance from the axis of symmetry?
When a concentrated force (F) is applied at a specific radial distance (r) in an axisymmetric model in Abaqus, the software automatically treats it as the total resultant force distributed uniformly around the full 360-degree circumference corresponding to that radius. This is because axisymmetric modeling inherently represents a 2D slice of a 3D structure with rotational symmetry (each point in the 2D mesh corresponds to a ring in the actual 3D geometry).
Abaqus internally converts the applied force (F) into an equivalent circumferential line load with an intensity of [F/(2πr)]. This ensures the correct total force magnitude (F) is applied consistently in the underlying 3D problem. So, you do not need to manually adjust the input force; Abaqus handles this distribution as part of its axisymmetric element formulation.
Yes, Abaqus treats the concentrated force in an axisymmetric model as a total force distributed uniformly around the circumference.
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