If I dilute 100mg of a particular pesticides, for example dinotefuran with an active ingredient of 20.0% in 0.2L of water. How do I convert this into ppm?
Thanx Ikbal.
One more, I diluted 200µL of Beauveria bassiana (commercially produced as BotaniGuardES) with spore number of 1.6 x 1010 in 0.2L of water. How do I convert this to ppm?
I agree with Ikbal Chaieb for the first answer
So this calculation in ppm is impossible
Hi,
I totally agree with F. Romain Fouelefack. The amount of B. bassiana is not expressed in units of measurement, but only in number.
The active ingredient in the 100mg is 20 mg that is going to be diluted into 0.2 L hence the dilution will be 20mg/ 0.2 L.
This becomes 200mg/2L which is 100mg/L.
As you know 1mg/L is the same as 1ppm so your dilution will be 100ppm
https://www.rapidtables.com/convert/chemistry/ppm-to-mg-per-liter.html
See this link
One thousanth of a gram is one milligram and 1000 ml is one liter, so that 1 ppm = 1 mg per liter = mg/Liter. PPM is derived from the fact that the density of water is taken as 1kg/L = 1,000,000 mg/L, and 1mg/L is 1mg/1,000,000mg or one part in one million.
https://www.unitconverters.net/concentration-solution/milligram-liter-to-part-million-ppm.htm
I agree with the Ikbal Chaieb's answer to question 1. Well explained as expected
If it was a sol, for exemple you did leaching or extraction, you have to convert the unity from mg/l to mg/Kg, so usually we use this method:
for example (leaching):
100g ->1L
the concentration of nitrite is : 2mg/l
so you do 2/100 (mg/g), after that you get 0.02*1000 to have 20mg(nitrite)/kg sol
- Badges
- Science topic
- Similar topics
- Biological Science
- Biota
- Eukaryota
- Fungi