what the chain reaction that happened duringphoto degradation of carmosine dye by ZnO, which leads to produce a quantum yield equal to 0.5.
Dear Sir. Concerning your issue about the mechanism for photocatalytic decolorization of carmoisine dye with ZnO at quantum yield nearly from 0.5. The degradation efficiency of dyes increased with increasing irradiation time under irradiation of fluorescent light. The photocatalytic activity of ZnO nanoparticles was better compared with that of TiO2 for MO; and the ZnO activity was the same as TiO2 for dye photodegradation. Kinetic behavior was evaluated in terms of the Langmuir–Hinshelwood model (pseudo-first order kinetic). The possible mechanism of photodegradation under fluorescent light was discussed. I think the following below links and the attached file may help you in your analysis:
https://www.witpress.com/Secure/elibrary/papers/SC08/SC08065FU1.pdf
https://pubs.acs.org/doi/abs/10.1021/ie049921z
Thanks
Dear Dr. Isam Eldin Hussein Elgailani ,
Much obliged for your answer.
I performed manuscript in my Ph.D for degradation of methanol to formaldehyde and have quantum yield 0.5, so, two molecules of .CH2OH radical can be given 1 molecule of formaldehyde during photooxidation by Bare and metal doped TiO2 . But now , I need idea to interpenetrate why the quantum yield of degradation of carmosine equal to 0.5.
Please, see the attachment paper for photooxidation of methanol and give me your opinion.
Regards,
Dr. Luma
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