The recoil force of radiation is known for spontaneous emission (for the radiation of an accelerating charge or dipole), when the photon field is empty. Is there any difference when stimulated emission is considered? Would it be enough to add an external force to the original radiative reaction-force without changing the original form of the radiative reaction?
Dear Peter,
In principle the calculation of the calculation of the radioactive reaction for stimulated emission is not so difficult, in general and without entering in the details. The idea is to calculate the frequency of the stimulated emission induced by unpolarized isotropic radiation. Once you have it you can calculate the wave length and therefore the moment. And finally you calculate its time derivative for obtaining the force associated to such radiation.
file:///C:/Users/daniel/Downloads/9783319051277-c1%20(1).pdf
Dear Daniel Baldomir
Thanks for your answer, but is not clear... The original Larmor-formula is derived for empty radiation field. Will be it changed for stimulated emission?
Could you attach again the pdf file, it cannot be downloaded?
Dear Peter,
Larmor formula is for the acceleration of a charge, but what I have understood for your question is that the stimulated radiation between two levels. This is very different concept and you have only a decaying of coherent photons within a dipolar approach radiation. This is well known in Optics and you have a clear formula.
If you copy and paste the above link you can enter to it. But you can do it shorter
9783319051277-c1 (1).pdf
Dear Daniel,
I haven't got quantum two level system. I want to see a purely classical theory of stimulated emission, but I'm missing the effect of the occupied photon field from the Larmor-formula and from the classical radiation reaction-force formula when stimulated emission is considered.
Dear Peter,
Hint:
"Stimulated emission is the process by which an incoming photon of a specific frequency can interact with an excited atomic electron (or other excited molecular state), causing it to drop to a lower energy level. The liberated energy transfers to the electromagnetic field, creating a new photon with a phase, frequency, polarization, and direction of travel that are all IDENTICAL to the photons of the incident wave. "
Check the word in capitals, I think it solves your problem.
The net change regarding momentum and energy exchange
is identical to emission, isn't it?
best regards,
Tibor
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