I try to prepare 100ml of a 1000 ppm Ni(II) solution by solving NiSO4.6H2O in ionized water. To do so I add 0.45g of NiSo4.6H2O to the water. i would appreciate if anyone tell me whether it is correct or not.
thank you in advance.
You can dissolve 1g of NiSO4.6H2O in the water, then bring it to a volume of 1L.
ppm means mg/L.
1000 ppm means, 1000 mg per 1 L.
thank you so much. I did exactly as what you said at first, but after a while I noticed that I`d had a 1ppm solution of NiSO4.6H2O although I wanted to make a 1 ppm solution of Ni(II),that was what I found a mistake!
Considering that 1 mole of NiSO4.6H2O has 1mole of Ni, and 1 mole of NiSO4.6H2O weighs 262.85g so it has 58.69g Ni(II). by using this number and knowing that a 1ppm solution of Ni(II) has 0.1g Ni, the amount of NiSO4.6H2O obtain: 0.45g.
Actually my problem is this: recently i read somewhere that for making such a solution you should dissolve a salt in your solution then by measuring the amount of a formed sediment you can say the ppm value. I don`t know if my method is correct or not? Mahsa Khajeh
Yes, you are right. sorry...
Please find the picture in the attachment. I hope to take your answer.
This is the method of solving the equation, but I do not know anything about the type of salt and the formation of sediments.
Exactly, your calculation is right, thank you so much. I think the number which I obtained , 0.45g, was to make a 100ml of a 1000ppm Ni solution. Our difference is because of the volume of the solution. I appreciate your help dear.
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