yeah, can't think of anything simpler than:

de2bi(0:7)

or if you want it in the order you typed it in:

sortrows(de2bi(0:7))

t=[0 0 0 ; 1 1 1];

    n=length(t);

    result=bsxfun(@times, [0,1,0],  dec2bin(2^n-1:-1:0)-'0')

Dear manoj,

Thanks, But I am not getting results as per my need.

Your code is given following answer

result =

0 1 0

0 1 0

0 0 0

0 0 0

0 1 0

0 1 0

0 0 0

0 0 0

I think this may help you:

http://www.mathworks.co.uk/help/comm/ref/de2bi.html

yeah, can't think of anything simpler than:

de2bi(0:7)

or if you want it in the order you typed it in:

sortrows(de2bi(0:7))

Dear Ghanasyam

Rahul G. Waghmare is given the correct code for your suitable output.

Instead of Num_of _bits=2 you put 2 as 3 and finally you will the answer

Dear Rahul G. Waghmare,

Your answer is working as per my need.

Thanks ones again

Dear Pete R Jones,

Your answer is an alternate solution, It can be used with some addition command.

Thank you