suppose protease enzyme was assayed at an initial substrate concentration of 2x 10-5 M. In 6 minutes half of the substrate had been consumed. Km for this enzyme substrate is 5x 10-3 M. Calculate k andVmax.

I tried to find the k using the formula,the rate=the chenge of [reactan] over time.

Rate=2 x 10-5/360s= 5.5556 x 10-8

I am not sure this is correct or not....and i just stuck here because i dont know which formula shall i use to find Vmax...

I got think about the Michaelis menten eqn,but the question not stated any type of order of reaction...so...i need help....