Experimentally, any power analyzer can directly find the efficiency of the circuit. If you don't have the power analyzer, than may be you can measure the current and voltage at both the input and output and calculate the power at both the ends. Even oscilloscope will work for it.
In simulation, the same procedure can be use. If you have high ripples in the output, you better to use RMS block, and digital display will give you both the input and output power.
Experimentally, any power analyzer can directly find the efficiency of the circuit. If you don't have the power analyzer, than may be you can measure the current and voltage at both the input and output and calculate the power at both the ends. Even oscilloscope will work for it.
In simulation, the same procedure can be use. If you have high ripples in the output, you better to use RMS block, and digital display will give you both the input and output power.
The answer of Muhammad Amir is satisfactory. Electronic circuits can be solved analytically using the so called approximate or the first order linearised models of the electronic devices specially when the count of the elements in the circuit is small. However when the circuit gets complex it may be suitable to use a numerical circuit analyser based commertial computer aided circuit analysis tools such as the very famous SPICE and its derivatives such as PSICE.
Solving the circuit one determines its node voltages and branch currents. As said before knowing the input and output voltages and currents one can determine the efficiency of the multiplier as the ratio of the delivered power to the load / power extracted from the input source.
One has to consider that the multiplier efficiency will depend on the load.
Thank you Prof Zekry for helpful answer, actually the circuit that I have complex, it has many non liner elements. Then I will try to find it by fining the input and output current and voltage; then by calculating the input and output power.
But how can I consider the load value in my calculations?
To determine the efficiency of the voltage multiplier circuit you apply a voltage source on the multiplier with a voltage Vi and load it by a load RL. The multiplier has a power rating say P, then the input current will be Ii= Pi/ VI, assuming the efficiency of the voltage multiplier is eta, then the output power will be po= eta XPi, Assuming the voltage multiplication ratio=Mv, then the output voltage will be V0= MvVi,It turns out that the output current Io= Po/V0= eta Ii Vi/ Vo= eta Ii/ Mv,
Then one gets an estimated output resistance as load RL= Vo/Io= MiVi/ eta Ii/Mv)= Mi^2Vi/ eta Ii= (Mv^2/eta) Vi/Ii = resistance transformation ratio X the equivalent input resistance Ri, where Ri = Vi/Ii,
One can use above formula to estimate the output load resistance.
Other way one can scan the efficiency eta as a function of RL and locate the value of RL at the maximum efficiency assuming certain input voltage and certain multiplier circuit.
You can cite this researchgate link. Now the researchers cite the answers on the researchgate. Indeed i derived the relations while answering your question. i made this many times while answering questions on RG.