Dear venkatesha,

0.1mol% of Europium Nitrate with TiO2 material is:

0.1 mol Europium Nitrate in 100 g TiO2. 

Molecular Weight of Europium Nitrate is 337.98 (anhydrous basis).

1 mol of Europium Nitrate= 337.98 g;  hence, 0.1 mol = 33.8 g

for obtaining 0.1mol%, your mixture should contain 33.8 g Europium Nitrate in 100 g TiO2.

Hoping this will be helpful,

Rafik

Dear venkatesha,

0.1mol% of Europium Nitrate with TiO2 material is:

0.1 mol Europium Nitrate in 100 g TiO2. 

Molecular Weight of Europium Nitrate is 337.98 (anhydrous basis).

1 mol of Europium Nitrate= 337.98 g;  hence, 0.1 mol = 33.8 g

for obtaining 0.1mol%, your mixture should contain 33.8 g Europium Nitrate in 100 g TiO2.

Hoping this will be helpful,

Rafik

I agree with Karaman

thank you very much Karaman sir..Will you suggest any reference papers for further study...

Dear venkatesha,

I recommend you to read the attached review:

Doped-TiO2: a review

ABSTRACT

Titanium dioxide represents an effective photocatalyst for water and air purification and for self-cleaning surfaces. Additionally, it can be used as antibacterial agent because of strong oxidation activity and superhydrophilicity. TiO2 shows relatively high reactivity and chemical stability under ultraviolet light (λ 400 nm) should allow the main part of the solar spectrum, even under poor illumination of interior lighting, to be used. Visible light-activated TiO2 could be prepared by metal-ion implantation, reducing of TiO2, nonmetal doping or sensitizing of TiO2 with dyes. This paper reviews preparation methods of doped-TiO2 with metallic and nonmetallic species, including various types of dopants and doping methods currently available. The mechanism of heterogeneous photocatalysis in the presence of TiO2 is also discussed.

Hoping this will be helpful,

Rafik

thank you so much sir...for your kind help

sir , if i need to dope 5%of any metals like au, ag, in a nanoparticle.... how i should calculate the amount of salt like aucl,agcl....

How can we calculate the weight of dopant in tio2 - 0.5 at wt%zn

I think, 100 g TiO2 and 0.1 mol% European nitrate mixture will be followed : 0.421158 g European Nitrate + 99.58872 g TiO2.

Dear All,

• I would like draw attention the value of 99.9 moles of TiO2 contains 7992gm it means 7.992kg !. Is it feasible ?

Please comment asap.

Thank you all. From above I got the idea about the compound doping in TiO2. If I want to dope Mn in place of Ti in TiO2 in mole/percent, then how will I calculate? Kindly reply. The precursors are manganese chloride and titanium isopropoxide.

How to calculate 0.5 wt% of Bi from Bismuth nitrate in TiO2

thanks for giving the answer.

you can calculate by using formula:

0.1%= (M.W. of Dopant / M.W. of Product) X weight of the product X 10-3 grams

this is useful in doping different rare earth elements as dopant concentrations while preparing phosphor materials.

This will help. Thank you for sharing your input.

I think Swagotom Sarkar is right.

Use the following formula

Concentration of dopant in grammes= (Molecular weight of the Dopant / Molecular weight of Product) * product's weight * 10^(-3)

@shuraik Kader sir can you please give example.. As I can't understand what is meaning of product's weight.. I want to calculate dopant concentration before actual chemical reaction to be occured.. Thank you for help

The following link may help:

https://www.youtube.com/watch?v=aFBUW-XockY

I need to prepare Li4Mn(5-x)Ti(x)O12 with Ti as a dopant. If x=0.1, how do I know the weight of Ti required to form the required compound?