I want to calculate the amount of organic and inorganic fertilizer that i need to apply in one pot. both the fertilizers are in solid form. the inorganic fertilizer has N:P:K 15:15:15. the radius of the pot is 7cm. I want to apply three dosages; 100, 200 and 400kg/hectare.
Depends on what your research question is: usually this kind of pot trials is not useful for fertlizer experiments. Calculate the fertilizer need on basis of the dry matter you expect to grow in the pot (based on 0,5% N) in dry matter and e utilization coefficient of 50% and supply this amaount in three dressings. 15:15:15 is not the best solution , but would work. Tell me what you plan and perhaps we can advise you better!
please give the height of the pot or the volume of the pot to calculating the amount of fertilizers for the experiment and the type of the plant that use in the experiment.
Hi!
It's simple elementary arithmetic: S(ha)=pi*r^2=3,14*49=153,94 cm^2;
1ha=100 000 000cm^2; 200kg/100 000 000cm^2=0,002 g/cm^2/0,15=0,0133 g per 1cm^2. And 0,0133*153,94=2,047 gramm per pot
Best regards!
Please provide the weight of soil the pot can hold to help you in calculation of fertilizers.What is the NPK recommendation? Are the nutrients in N,P and K or N,P2O5,K20 terms?You did not give any detail of organic manure.
Thank you everyone for your replies. Actually the experiment is for commercial purpose. The company that wants me to carry this out does not want me to base my results on dry matter.
I am using the fertilizer to grow Impatiens Balsamina flowers. Which will be later sold. So I will have to base my results on the growth of stem and yield of flowers.
The Pots are terra-cotta plastic pots of height 12 cm and 14cm diameter.
The N, P, K vallues of the organic fertilizer are as follows (all values in %w/w) :
Nitrogen (as N) = 5.1
Phosphorus (as P2O5) = 3.8
Potassium (as K2O) = 4.1
and the C:N ratio = 8:1
The values for the inorganic compound fertilizer were just mentioned as N:P:K (15:15:15).
Mr. Moiseev, I got that answer too. However, I cant help but think that 2 kg of fertilizer for such a small pot is too big of a value. And if 2 kg is the correct answer, should i give this amount in small doses every two weeks? and in that case, how should i determine the dosage?
I am also growing spinach in separate pots of same size but they are only 10 pots. I am sort of in a bind as the company prefers that I not put the plants in oven. So If there are any suggestions on how else I can proceed with this I would be much obliged
Please carefully read my answer, no 2 kilograms, but 2 grams per pot. More precisely, can be calculated knowing the density and weight of the soil in the pot.
Oh! I thought with the comma it meant 2000 grams. So sorry. Thank you so much! This is great.
find the mass of soil per hectare by multiplying volume with bulk density and then find per kg nutrient requirement. what ever the soil you are taking multiply that with per kg value.
Sabiha,please see the following link in researchgate for more details on calculating fertilizer nutrients in pot culture studies.
https://www.researchgate.net/post/Calculation_of_fertiliser_for_potted_experiment
The general roe of thumb in such cases is use 1.5 to 2.5 Kg of chemical fertiliser in 100 sq. ft. of the garden and use 10 to 15 kg of organic manure in 100 sq. ft. of the garden. This is a very rough way to calculate and if I assume the size of pot as 0.06 sq. ft. then the chemical fertiliser needed comes to about slightly above one gram. It matches nearly with the scientific suggestion by Moiseev K G. Of course you have to adjust this to your research needs.
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