Hi, what is the simplest way to interpret the effect of symmetry of benzene on its electronic transitions in the UV region?
Molecular Vibration of the benzene molecule gives the "hand" pattern in the UV Absorption specturm. see Z Phys D Atoms Molecules and Clusters, 1991, 20,43-46. Vibrational (and sometime rotational) fine structure is present in the benzene spectrum.
Thanks Mathew, in fact what I needed is how to explain the below paragraph :
",,,,,,,This is due to the symmetry of benzene; it is not possible to have an excited
state involving all three bonds in benzene because this would mean that the dipole
(polarisation of the chromophore), a two-dimensional concept which is created in the
excited state, would be symmetrical and thus would have to exist in three dimensions
rather than two."?
Mr. Balakit,
The attachment considers all aspects to the topic of your question, and seems to need no further analysis. So, this is the simplest and, in parallel, a comprehensive manner to explain the relationship symmetry-orbital contribution-electronic spectra in C6H6.
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