Hello Abdul,

My calculations says as follows:

The method used 1.5M AgNO3 200 ml solution.

The mol wt of AgNO3 is 169 and Ag is 107.

1.5M AgNO3 200 ml solution will have 50.7 g of AGNO3

This soln will offer 32.1 g of Ag at the end of reaction (considering 100% reaction).

Similarly, the PVP 6.25x10-3M solution (600 ml) will offer 37.5 g of PVP.

Hence, at the ned of reaction the total bulk of NP will be 32.1 g Ag + 37.5 g PVP

This totals 69.6 g of Ag-PVP nanoparticles.

You can concentrate this NPs according to your need by centrifugation, to make mg/ml solution of your interest and requirement.

Best wishes

Rakesh

So if the above reaction is correct, then your 25g of AgNO3 which contain 15.8g of Ag should lead to 34.3g of Ag-PVP nanoparticles. If you know or can measure the size of your nanoparticles then the volume concentration [mg/mL] can be converted to a number concentration [number of particles/mL].

Thank you so much Mr. Rakesh. I appreciate your effort. 

Thank you very much for your answer Mr. Ulf Nobbmann. (y)

A related question and answers can be found here: https://www.researchgate.net/post/How_to_get_the_weight_of_nanoparticles_in_Moles

Should your question be "approximately how many Ag nanoparticles we can get?" not how much.....

Thanks for your comment Mr. Alan. 

Actually, i need these nanoparticles in a powder form, so that i can weight it out.

Say, i am getting an approximate 50g amount of Ag nanoparticles.

Is this amount countable??? I don't think so. 

If yes, then you are right Mr. Alan.

You may want to read attached: "Nanoparticle counting: towards accurate determination of the molar concentration", Chemical Society Reviews 43(21) · August 2014

@Abdul   Mass is conserved so you can't get 50 g of Ag from 25 g of AgNO3... Ulf has indicated the correct calculation above.  You must remember that you're also stating that you'll bind the Ag nanoparticles (~ 16g) to PVP.  As another point you can't get the nanoparticles in powder form - to preserve their < 100 nm status (the definition of nano) as free, discrete, independent articles, you'll need to keep them in colloidal suspension.  See a recent discussion on RG: https://www.researchgate.net/post/How_to_deagglomerate_then_disperse_silica_nanoparticles_in_powder_form

A dry powder ('nanopowder' is an oxymoron as there are no free independent discrete particles of 20 nm in a powder even if the primary particles are 20 nm) is a fused collection of sub- and post-micron particles.  They are aggregates not agglomerates. See:

Nov 11th, 2008. Dispersion and nanotechnology  http://tinyurl.com/hpywsge

November 3rd, 2015 Adhesion and cohesion  http://tinyurl.com/zwb2wlh

“If the particles are agglomerated and sub-micron it may be impossible to adequately disperse the particles……The energy barrier to redispersion is greater if the particles have been dried.  Therefore the primary particles must remain dispersed in water….”

J H Adair, E. Suvaci, J Sindel, “Surface and Colloid Chemistry” Encyclopedia of materials: Science and Technology pp 8996 - 9006 Elsevier Science Ltd. 2001 ISBN 0-08-0431526