From conventional energy and momentum we get the equation.

(mc2)2 = E2 (1 - v2/c2 )

This question depends on how quickly energy increases compared to velocity.

The conventional equations do not make a complete set. Something must be added. The least troublesome assumption Is that h the Planck's constant does not vary with energy. This case is the GR which covers all 4D situations except maybe the extreme high energy.

Solution continues by integration.

dE = v dp

pc = E (v/c)

dE2 =c2dp2

L is used as Einstein did for the ratio of locally measured light speed to standard light speed in cases of gravity and other acceleration.

(mc2)2 = Eo2 (1 - v2/c2 )( 1 + (v2/c2)/L2 )

Results for constant h are suggesting that mc2 measured by a traveler does decrease as acceleration continues for any real L in General Relativity.

Does Locally Measured mc2 Decrease At High Speed?

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