Hi guys, I have a question.
I have extracted 0.5 g biomass using 5 mL of solvent. From this, 40 uL were used to calculate the total phenolics content (TPC).
40 uL extract + 1560 uL distilled water + 100 uL Folin reagent + 300 uL Na2CO3. Using absorbance of 725 nm, and based on gallic acid calibration curve, we have only got 25 mg/L GAE. How can I convert it to mg/g biomass?
Does the dilution using 1560 uL distilled water affect the calculations?
Thank you.
No if the calibration curve was constructed considering 1600 uL of standard.
To convert: 25 mg/L * 0.005 L / 0.5 g
Yes exactly, if you considered a condition for your standard and your unknown sample, the effect of constant conditions ignored
Many thanks for your answer Omar and Farhad.
So to convert mg/L GAE to mg/g GAE, I just can use TPC= C x V / M ?
- Badges
- Science topic