Can the size of TiO2 powder be becreased if it was dissolved in 2.5 M NaOH, then Precipetated by 1 M conc. HCL, according to the following equations:
TiO2 + 2NaOH = Na2TiO3 + H2O
Na2TiO3 + 2HCL = 2NaCL + TiO2 +H2O
??
and if it is not possible, what will be the best method to prepare TiO2 nanoparticles with size less than 50 nm ??
Thanks in advance.
Hello dear Alaa,
I am suggesting you a reference that could help you with the procedure for obtaining that particle size of TiO2:
Article Titanium dioxide nanoparticles: A review of current toxicological data
Remember also that particle size will depend of a lot of aspects, please, check other references if you a doubt.
With kind regards,
Julián S.
Alaa A. El-Robi This reaction may result in different products such as Na2TiO3, Na2Ti2O5, Na2Ti3O7 and Na4TiO4 or a mixture of them. Theoretically, the MCV should increase while the crystal size will decrease. However, there is no cut answer for this question without doing XRD and analysis of its data to have the right answer (Data analysis normally requires a person trained on a specific software designed for this purpose).
All the best,
Hany
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