If Iqpt/Q = 1 and
the number of airborne quanta inhaled
by susceptibles equaled the number of
susceptibles, some susceptibles would escape
infection and others would inhale
more than one quantum. According to
Poisson's law of small chances, the probability
of escaping infection in this special
case would be approximately e-1 or
0.37, where e is the base of natural logarithms
with a value of approximately
2.7. The probability of acquiring infection
would be (l-e-1
) or 0.63, and the
total number of infections would be
S(I- e-1
) . Thus, in this special case where
Iqpt/Q = 1,63070 of susceptibles would
be infected with random distribution as
opposed to 100% with even distribution.
The general expression, based on these
physical relationships, is:
C = S(1 - e-Iqpt/Q) ?
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