Let a=1 b=1 c=1 are 3 inputs to exor gate then output is 1
(1⊕1)⊕1=0⊕1=>1
If the same inputs applied to exnor gate i am getting same output
(1 exnor 1 ) exnor 1= 1 exnor 1 = 1
For all 8 possible inputs(3-bit) I am getting same output for exor and exnor gate.
My doubt is
1) Is it possible to get same output for both exor and exnor gate for odd number of inputs.
2)Is 3- bit exnor gate exists?If exists is it obeys associative law? If obeys is it works similar as exor gate.
Hi
That is not how a 3 input XNOR works.
You have written the expression for the case where you use two 2-input XNORs.
A 3-input XNOR is ~(A xor B xor C) and is very different from ((A xnor B) xnor C) which is equivalent to ~( ~(A xor B) xor C) .
Attempt to evaluate the two expressions using De Morgan's laws of Boolean Algebra.
I hope this helps you.
Yes... for all odd inputs ..Exor and Xnor will get same output.... Exor =(Exnor)' is valid for even number. for add number both are equal....
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