Hello !
I am currently doing a simulation of a 2D hollow cylinder (plane-strain assumption) falling on to the ground with a initial velocity of 5m/s from a height of 2m and allowing it to keep bouncing until it comes to rest. I carried out this simulation and obtained the first graph and again i restarted with a new step to obtain the second graph. Both the graphs are attached below.
Problem:
I want to join the two graphs (meaning the end point of the first graph should be the start point of the second graph). I tried by first creating the XY datas as shown in the attachments. Then i tried TOOLS -->XY Data--->CREATE----> OPERATE ON XY DATA ----> OPERATOR : append ((X,X....)) and I managed to get a graph with an expression---> append (("XYData-1", "XY Data-2")) as shown in the third attachment.
But as stated before I want the end point of graph 1 to be the start point of graph 2. I am not able to figure out a right expression for it. Please help me to fix this problem. Any help in this regard is appreciable.
Thank you.
You could just simply add to the x-values of the second graph (before appending) the last x-value of the first graph, so as to obtain step time of the second graph that ranges form 1 up to 2.
otherwise you could define the time step function of your second simulation that ranges from 1 to 2.
I also suggest to proceed as Stefano Gabriele suggested. These are the smartest ways.
In addition to previous answers within Abaqus environment. You could use report function output to a data file and then using Excel to plot with more functions. It is also the best way to present your paper.
Good luck.
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