If I have a data of 10-fold diluted sample like 26.80, 26.52 and 27.23 (mean value 26.85). This has standard deviation of 0.357. Actual concentration will be product of 10 x 26.85 (268.5). Do we need to multiply standard deviation with 10 also?
Assuming that the counts change linearly with the degree of dilution/concentration, then, yes: if you want to express (estimated) variation in the undiluted metric, multiply SD by 10 (for variance, it would be 10^2, or 100 times larger).
Yes you can multiply the diluted SD by the factor as indicated by David Morse . However, you could also try multiplying the diluted concentrations with the factor to get the undiluted concentrations, then you can confidently determine the mean and SD. Best,