In SMR calculation, In calculation of adjustment factors F1 and F2, If amount of dip is more than 45º and I try to calculate from their respective formulas it gives very high value and gives a large value of product of F1*F2*F3 with negative sign which give rise to negative value of total SMR.
So, In F2 if dip of the joint will be more that 45º, Should I assume 1.0, but this will not satisfy the formula given for F2 calculation i.e. tan2βj? Similar situation with F1?
What should be done to overcome these abnormal values?
Hi Tariq,
Try this
http://personal.ua.es/en/ariquelme/smrtool.html
Best regards
Dear Adrian,
Earlier I tried that ..... but Excel sheet provided in that is locked.
Last week I added a matlab gui. It is a compiled window to calculate auxiliary angles and factors, which aims to aid students to manage SMR. If it doesn't work please tell me.
Try this is you are using a 32 bits machine:
http://personal.ua.es/en/ariquelme/documentos/smrtool/smrtool-installer-windows-x32.exe
Or this if your machine is 64 bits
http://personal.ua.es/en/ariquelme/documentos/smrtool/smrtool-installer-windows-x64.exe
Dear Adrián Riquelme,
During input, software have only option of one discontinuity. However, In wedge failure case factors considered are 2 sets of discontinuity intersecting each other, relative slope orientation and also on friction angle.
In manual calculation we calculate from trend and plunge of line of intersection. Should I use the same?
Dear Tariq,
You are right, you have to use trend and plunge of line of intersection.
BRMR is always equal or major of SMR. I used a lot SMR classification and the right formula is
SMR = BRMR - I F1xF2XF3 I + F4.
F4 is zero or negative.
Stefano Devoto , the F4 value is -8 when deficient blasting, 0 when mechanical excavation or +8, +10 or +15 when smooth blasting, presplitting or natural slope respectively. It can be positive.
When I used SMR, I akways obtained SMR ranks lower than BRMR.
F1 x F2 x F3 usually is greater that the rating of F4 . More over, It is strange that the SMR is greater than BRMR because BRMR is the quality of rock mass and how a natural slope can improve a quality of rock mass?
Always think about what kind of lithology You have it’s impossible to evaluate soil rock like marl,clay,shale because the SMR is done for risky hard slopes you never see that soil create dangerous slope coz it is weather easily and not creat dangerous cliff that you evaluate it
what I see you evaluate soil like marl and shale and SMR useless for this kind of slope and you got negative value
Dear Tariq,
These articles might help:
Article An empirical method for slope mass rating-Q slope correlatio...
Article Assessment of rock slope stability by slope mass rating (SMR...
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