The polymerization reactions are accompanied by continuous decrease in entropy. Albeit this loss affects the Gibbs free energy, they are facile and feasible. How?
Radical polymerization processes are usually accompanied by high reaction heat (exotherm) which overcompensates the entropic effect.
Radical polymerization processes are usually accompanied by high reaction heat (exotherm) which overcompensates the entropic effect.
The change in the Gibbs free energy for isothermal and isobaric reaction may be given by
Del G = Del H -T Del S = 0, which is equal to zero for reversible process. Then one has,
Del H = T Del S. Where Del is a finite variance or difference. Del operator implies { Product - Reactant} : For one mole of reaction Del Hm is the molar enthapy of reaction. İf it is positive that means reaction is endothermic and otherwise it is exothermic.
As Dear Gyorgy mentioned properly, the negative molar entropy variation shows that this polymerization reaction is exothermic there would be heat generation during the reaction.
Dear Sai Siva unfortunately your remark on Gibbs free energy is false. This is reversible reaction and the Gibbs free is invariant under the isothermal and isobaric reaction. For a natural process Gibbs free energy should be negative but it is never positive (unnatural process).
Entropy: A concept that is not a physical quantity
https://www.researchgate.net/publication/230554936_Entropy_A_concept_that_is_not_a_physical_quantity
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