I have Divinyl sulfone (DVS) which is in the form of a colourless liquid. On the bottle the specifications are 25g.(doesnot mention the volume in which it is dissolved!) Now my question is if I want to add 2wt% of DVS(ml) how will i do the calculation? Any ideas will be appreciated
Most probably it is not dissolved; however, typically, can contain a minor amount of hydroquinone as inhibitor, as it should be clearly indicated at the product label and at the Material Safety Data Sheet (MSDS). This substance is considered hazardous.
It is not an assumption & the mass of divinyl sulfone is 1.177 g in 1 mL of solution (which includes solute + solvent). Since there are 25 g DVS, then the total volume of the solution in the bottle is 21.24 mL. [ 2 wt%of DVS(ml)] means getting 2g. solute out of 100 mL solution, hence, it will be (21.24 X2)/100 = 0.4248 g. This is the required mass for the experiment and it is found in (0.4248/1.177) = 0.361 mL of solution.
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