Hi everyone,
I was recently doing a simulation and actual measurement of a rectifier circuit, using the series diode SMS7630-079LF (Breakdown Voltage=2V). The output DC voltage obtained by my simulation did not exceed 1V (max Vout=0.93V when Pin=20dBm). However, the maximum DC voltage measured in the actual test was 3.4V, which is obviously incorrect.
I checked the circuit and there seems to be no problem. I am very confused.
Can anyone help me with this problem?
The AC input voltage is in a form called Root Mean Square RMS, Vrms. This is a means of quoting a voltage to be able to use it directly to calculate power. For example 12 volts RMS applied to a 10 ohm resistor would dissipate V^2 / R = 144/10 = 14.4 watts. However the AC sine wave is not 12 volts all the time, it is alternating and goes down to zero and up to a voltage higher than 12V. That it called the peak voltage Vp = Vrms* sqrt(2) = 12* 1.414 = 17 volts.
If you rectify this voltage with a full wave bridge rectifier, you will lose about 0.7 volt across the conducting diodes so you would get about 17 - 2*0.7 = 15.6 volts.
The AC input voltage is in a form called Root Mean Square RMS, Vrms. This is a means of quoting a voltage to be able to use it directly to calculate power. For example 12 volts RMS applied to a 10 ohm resistor would dissipate V^2 / R = 144/10 = 14.4 watts. However the AC sine wave is not 12 volts all the time, it is alternating and goes down to zero and up to a voltage higher than 12V. That it called the peak voltage Vp = Vrms* sqrt(2) = 12* 1.414 = 17 volts.
If you rectify this voltage with a full wave bridge rectifier, you will lose about 0.7 volt across the conducting diodes so you would get about 17 - 2*0.7 = 15.6 volts.
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