I have a query regarding the efficiency of QZS converter, why is it around 91-93%, is it because of the upper limit of duty ratio (50%). I proposed a converter which is similar to QZS but the output side capacitor (C0) is charging for a period of (1-D)Ts. In this case, can I say the the efficiency is similar to the cases of D=100% converters which is around 95%.
Converter Details:
Input voltage= 40 V
Output Voltage = 400 V
Power Rating = 500 W
Switching Frequency = 50 KHz (Hard Switching)
Duty ratio = 42%
Voltage Gain =1/((1-2D)(1-D))
The efficiency of a Quasi Z source DC-DC converter is around 91-92% due to the inherent energy-recovery switching technique. This technique allows the converter to reduce switching losses, which increases the overall efficiency of the converter. Additionally, the use of a quasi-impedance source (QZS) allows for increased power transfer in the converter, resulting in increased efficiency.
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