Hi Fortunato

You are true, I investigated a lot using exfor data , it would happened some combinations before, but it is a pity that such energetic reaction is not possible to make it using a D accelerator.

It is a pity in Exfor database does appear very few cross sections of elastic scattering, do you think this formula is correct? ( I obtained it from coulomb repulsion)

barns=2.1277*(Q1*Q2/MeV)^2, where MeV are the megaelectronvolts of Q1 sent again Q2.

I am not sure, but is the reaction D+D=He4+nothing prohibited because in this kind of processes you cannot conserve at the same time energy and momentum? Do you need at least a photon emission?

Yes, it emits a gamma.

Where could I obtain the non elastic scattering?

My answer is generalized for all fusion of any two isotopes.

Most fusion events have the same number of particles on the left and right hand side of the state equation.  Most fusion events of two particles produce a fusion, followed by a fission into two particles.   I know of no theory that predicts particle conservation, just it's been experimentally determined.  I've been reading up on "atomic collisions," which  you might search more on using those keywords.

A short answer is conservation of momentum.  The two particles total momentum on both sides of the state equation must be conserved.  Thus, if two particles hit, two particles must depart, at appropriate angles and energy.  The exception is the truly head on collision, where just one particle can conserve momentum.  But what is 'head' on for two bags of quarks?

Looking at the details, two nuclei collide in one of several ways. Direct head on is rare, and the quarks intermingle, forming a single nuclei, that might not fission, but most often does, for most all isotopes, as established by experiment.  A glancing blow, where the two nuclei 'touch' each other, results in immediate fusion, and attempts by the nucleons/quarks to establish the 'lowest' possible energy ground state, means something must be ejected, to release the kinetic energy from the two nuclei's velocities, that resulted in collision.  This release can be in the form of radiation, but is most often a particle, like neutron, proton, a pair of such, commonly an alpha particle, or a fragment that is larger.

Why a particle over radiation?  Some say the particle contains more energy than radiation and that's how it gets decided.  If the excited state is too high, then a particle with excess velocity is ejected.  If the excited state energy is low enough, then radiation might result.  But I have not read this is a 'rule', just conjecture, and is not followed for all isotopes.

Another way is for two particles to approach each other, and one fragments, where in the case of D+D, the only fragments possible are n and p.  And one of those fragments can fuse with the unfragmented D.

What actually happens?  You would have to look at the quarks and QED and such, and establish 'ratios' of results based upon angle of collision and point of intersection.  I wonder if anyone has done that.  And for what elements.  Janis and Empire supply some collisions, but only based on database queries, so one would have to look at their referenced sources, for both theoretical and experiment results. 

Perhaps it would be happen using another ions that works as catalysts,  that take part in the reactions but at the end they appear again after it, 

I read the other day that D+D takes place primarily by one D having it's neutron knocked off by the second D, and the first D's proton is fused with the second D.

Regarding other ions making He4, the known set of collision data for all isotopes should be searched by you, to look for outcomes that produce He4.  There are literally tens of thousands of collision combinations, and some do produce alpha particles. I looked for this answer about 6 months ago.

If you are looking to make Helium, or alpha particles, of those known collisions, alpha particles are one of the most common fragments.  Very expensive way to make Helium.

Would you post more background or the goal of your question?

I am designing next Pulsotron-3 fusion machine that works with D+D fusion (and other combinations). It would be a good point (but almost impossible) to fuse them without neutron generation and increasing the obtained energy by injection of other components or increasing the pressure to maximum

Generation of billions of neutrons would destroy any fusion facility.

It is better using other aneutronic combinations

>There are literally tens of thousands of collision combinations

Yes, they are but not all of them have enough barns

Ah, a new Pulsotron-3 design.  Very good.  And good luck.  I agree neutron generation is quite bad.  D+D is not going to provide long term feasibility, I believe. 

Creating a preferential direction of neutron emission would allow easier collection of them.  Thus, to remove them from the chamber and neutralize them, like tokamaks are attempting.  Having a very narrow injection beam is my first thought.  Limiting degrees of freedom with polarizing magnetic fields might assist in that.  And encourage a higher fusion probability.  Creating a volume of space where the neutrons can be trapped and 'burned' up, would be an additional feature.  You mentioned that in a different question. 

Doing all of the above would be a complex solution direction. 

Does your design have ash collection/removal?

>Does your design have ash collection/removal?

Not yet, but I should do!

In short term I will present Pulsotron-3 and Pulsotron-300k here in RG by upload a poster with main specifications

About neutron collection, I will take notes of your ideas.We could obtain narrow beams and axial compressed plasma.

Our timeline is first generate some neutrons using D+D to demonstrate we make fusion, and then go to clean fusion, then we could try another ways

Because D-D needs much higher temperatures than can normally be achieved – plasma temperatures of 150 – 200 million degrees C will enable lots of D-T fusion – but not very much D-D fusion (which requires temperatures in the range 400 – 500 million degrees C).

If you could do D-D fusion, you would produce Tritium and a proton from one branch – and with equal probability – He3 and a neutron from the other.  The temperature for D-He3 fusion to occur is even higher, so this would not occur much – in fact you would quickly end up with a D-T fusion reactor again as this would dominate.  You would make quite a lot of He3 which would not easily fuse.