We know that these elements are non-carbide formers. Therefore, C is more likely to be present in the solution which should make the austenite more stable. By this logic, adding these elements should make austenite stable up to an even lower temperature.
Dear Arka,
Good afternoon!
I always try to keep in mind that C is an interstitial alloying element while Al, Co and Si are substitutional alloying elements n Fe based alloys (like steels).
That means that Al, Co and Si will "take the place" of Fe atoms in the crystals, differently than C, B and N that will be in the interstitial positions in both austenite and ferrite crystals...
In Fe alloys there are only 4 gammagenic alloying elements, as follows: Ni, Mn, C and N. These 4 chemical elements are, ALWAYS, austenite formers in Fe alloys.
Si is a strong alphagenic element. It means it is a ferrite former.
I would as well keep in mind that both Al and Si have strong affinity with oxygen, been considered deoxidant elements in Fe based alloys.
What I can guarantee to you is that Co will always shift the TTT curve to the left... But I do not agree that Al and Si will do the same.
Co is a very interesting alloying element in Fe alloys. Keep in mind that Co is neighbour of Fe in the periodic table! I would tell you that the important effect of reduction of stacking-fault energy (SFE) that Co creates in Fe based alloys may be the answer to this particular effect that Co will always shift the TTT curve to the left... But it is something that is not 100% explained yet.
Very interesting question... Thank you!
I hope to help you. If it makes sense to you, I invite you to read some of my papers...
And join our research team! You are very welcome!
André
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