When I was making CH3NH3SnI3 solution, equimolar of SnI2 and CH3NH3I were dissolved in dimethylformamide to form 40 wt% solution. But the solution was dark and not transparent instead of being transparent, is it because SnI2 was not pure and was partially oxidized to SnI4? And DMF can only dissolve polar compounds?
I would not expect a colourless solution ― Stannous iodide (SnI2) is a red-orange solid, which can be thought to be either solvated by the charged resonance form of dimethylformamide (DMF), or to even form a neutral solvated complex having DMF as ligand. DMF can also act as hydrogen bonding agent toward methylammonium iodide, CH3NH3I. The last has also negative and positive charge centres, and may compete with DMF to form CH3NH3SnI3 perovskite, which is dark brown when in crystalline form.
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