Why are MOS capacitor calculations C(measured) normalized as C(mes.)/Cox? Can anyone give an explanation?

12 December 2013 1 5K Report

Also what is the true difference between built in potential and barrier height in the case of an MOS capacitor?

I think, this is because the measured capacitance is equal to the capacitance of the oxide in the cases of accumulation and inversion. If you want to compare the properties of the depletion layer beneath the oxide of two devices, it is much easier for the normalized graphs.

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