I have two functional groups aniline and 2-aminooxazole in my compound and I want to react it with aldehyde which amine will be reacted in this compound? or in another ward
which compound is more basic aniline or 2-amino oxazole?
I also assume that 2-aminooxazole is more basic. Aromatic amines have more resonance structures when unprotonated. This provides some stability to the unprotonated state and causes aromatic amines to be much less basic than aliphatic amines. Aniline has generally more resonance structures than 2-aminooxazole which is why it should profit more strongly from staying unprotonated.