Electromagnetic waves are having electrical and magnetic field perpendicular to each other always
Dear Satish,
I don't understand the relation of the electromagnetic waves with " pushed vehicles in its envelope". But if by the "long waves" you mean that they have a long wave length, then they energy E is very high (economicall expensive) and their linear momentum p very small. Therefore a scattering of them with the "vehicle" cannot give it a great force, i.e. they cannot help to much the change of motion.
Dear Daniel,
Why large wavelength should have high energy? It should be other way round.
Dear Gokaran,
The energy is proportional to the frequency and the frequency decreases as the wavelength increases because their product must be constant, i.e. the velocity of the light.
Dear Zbigniew,
I agree with you if the frequency decreases it also does it the energy. And I always assume a given density of photons on the surface vehicle.
It is true that this is taking the wavelength , as the data given in the question. There are other forms to understand it but this one must coincide with the macroscopic electromagnetic one which also depends of the frequency for the energy density and for the density of momentum ( Poynting vector).
Anyway, this question needs (at least for me) a better explanation and I only tried to explain that the long wavelength is for low momentum and therefore with associated low force, which seems to be the opposite to what is wished in the question.
Dear Zbigniew,
Wave you mean pulse? Because single wave energy always depends on the frequency or wavelength only.. Whereas a pulse, generates after superimposition of various photon of same wavelength, have very high energy in very short interval...
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