Ferrozine (disodium 3-(2-pyridyl)-5,6-bis(4-phenyl sulphonate)-1,2,4-triazine) is a water-soluble Fe(II) chelator. When chelated to iron, the complex absorbs light at 562 nm (molar absorption coefficient = 27,900). Copper can also be bound by ferrozine, however copper binds more strongly to another chelating agent, neocuproine.

          Iron can be released from protein through oxidation with acid-permanganate (1 hours at 60oC). Excess permanganate and released iron can then be reduced with ascorbate (RT for 30 min). Released iron must be kept at a pH of 4.5 – 5.0 for it to remain soluble. Acid-permanganate is an equal mixture of 1.2 M HCl and 0.285 M KMnO4

       Given that the Mr of haemoglobin is 68000 and that for serum albumin is 66000, calculate the number of molecules of iron per molecule of protein.  Use the known textbook value for the amount of iron in haemoglobin to calculate the purity of your sample.

Hint: a sensible strategy might be to start by constructing a calibration curve for the reaction of ferrozine with iron. Assays will need to use a control protein (non-Fe containing) for reference.

Another hint: A ratio of 1:5:10 would be appropriate for reagent B: acid-permanganate: sample.

Materials provided:

Haemoglobin (1.5 mg/ml)

Bovine serum albumin (5 mg/ml)

Ferrous ammonium sulphate (anhydrous?)

1.2 M HCl

4.5 % (w/v) (0.285 M) KMnO4

Reagent B containing:            6.5 mM Ferrozine

                                                13.1 mM neocuproine

                                                2 M ascorbic acid

                                                            5 M ammonium acetate.

More Jason Hughes's questions See All
Similar questions and discussions