As electron do not gain energy in presence of magnetic field they just change their path, so will temperature change on increasing or decreasing magnetic field?
hi
Just a conjecture ..I suppose you are referring to | mv^2 / r| = Florentz = |Q(vXB) |=QvB . We can see v changing with B so kinetic temperature will change . Bremsstrahlung may bring in peculiar quantum effects..depending on strength of B and relativity
Cheers
Dear Joshi, In his first answer, what Prof. Baig means is that when you increase the magnetic field, the confinement of the plasma tends to increase, so the effect is indirect. Basically, the reason is that when the magnetic field is increased, the Larmor radius is decreased, therefore the characteristic length in the random walk giving rise to (a part of) the transport coefficients is also decreased. This means it takes more time to the input power to be diffused to the edge of your plasma, hence the temperature gets higher. But if there's no input power, just increasing the magnetic field will not increase its temperature.
In practice, there is always at least a small input power, be it only to maintain ionization to a sufficient level.
The only effect of the static magnetic field on the plasma temperature is to induce an anisotropy in tempearture, where the temperature in the parallel direction is different to the temperature in the perpendicular direction.
You may search the key words "betatron" and "Fermi". Hope it will be helpful. Cheers.
Dear joshi, the temperature is proportional to plasma energy. The magnetic force(F=v^B/c) is always perpendicular to the velocity of a charged particle and consequently, their internal multiplication which characterizes the particle energy variation per second is zero. Therefore the mean value of plasma energy is not affected by the magnetic field.
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