Regards dear researchers,
Would someone help me to find the value of thermal expansion coefficient of Molybdenum (IV) oxide (MoO2)?
I tried to search but as of now i cannot find the exact value..
Thank you for your assistance.
From the topic
Thermal Expansion
The formula used to calculate thermal expansion coefficient
for metal halides and oxides is given as:
α≈ 0.038/ Mp - 7.0* 10^-6 K^-1
Now Mp of MoO2= 1373 as reported in ( Wikipedia) Molybdenum (IV)oxide
α≈ 0.038/ Mp - 7.0* 10^-6 K^-1
at 20C
2.76766*10^-5 -7*10^-6 K-1
27.6766*10-6 – 7.*10-6 K^-1
20. 6766 .*10^-6 K^-1
Dear Manohar Sehgal
Thank you very much for your answer. It was very helpful
Dear Manohar Sehgal
Would you kindly suggest me some reference related to the equation above for further studying?
thank you very much for your assistance
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