I am working on a space rover project, where the surface is supposed to be like Martian sand gravel mixture which has a static coefficient of friction as 0.6.
Now the weight of the rover is 50 kg and is being driven by 6 wheels of diameter 24 cm. The friction coefficient between the wheels and the ground is 0.58. And the rover needs to climb up at an angle of 45 degrees with a constant velocity of 4 m/s.
If any information is being left, please assume it as a variable x and help me finding the net torque required in terms of x to drive the system.
Please do mention whether you have found torque of a wheel or entire rover.
Please provide me with some rough values or a range of values where my torque requirements should fall on.
Please try to be more specific as I need to make it as perfect as possible in order to get the best results.
I had to solve comparable problems to yours in my 100-level undergraduate physics course many decades ago. My course instructor was able to help me understand what was needed. I cannot imagine the underlying physics has changed since then. Have you tried asking at that level?
"I am working on a space rover project ... the weight of the rover is 50 kg."
Presumably, 50 kg is the rover mass. The weight is gravitational force which depends on the planet you are moving on.
Is it a joke? Angle is larger than atan(0.58)=30deg, therefore rover will slide if engaged brakes. It is very bad idea to climb a slope where static stability is impossible.
Equation nonetheless..
T/R+u*cos(A)*m*g=sin(A)*m*g
T=R*m*g*(sin(A)-u*cos(a))
T-torque, R-radius of wheel, u - friction coefficient, A - slope angle, m - apparatus mass, g - local gravity
The speed is not in equation - it determined by motor output power, not by torque (torque only sets acceleration)
Overall, i agree with Jeffrey J Weimer. The question is too simple. The era of networked brains has finally came..
- Badges
- Science topic
- Similar topics
- Engineering
- Mechanical Engineering