Hi Keshav Bhatnagar ,

This might not be exactly what you need, but should give you a reasonably good idea what approach to take based on the equipment used in the protocol you are trying to replicate and the equipment available to you:

http://vesicles.niifhm.ru/

Some of the theory to help you understand what calculations are being done in the background can be found here:

https://handling-solutions.eppendorf.com/sample-handling/centrifugation/this-and-that/detailview/news/adapting-centrifugation-time/

Hope this helps!

To determine the equivalent of a 2 hour 100,000g spin on a 48,000g centrifuge, we can use the concept of relative centrifugal force (RCF) and the formula:

RCF = 1.118 x 10^-5 x r x (rpm)^2

where r is the radius of the rotor in centimeters and rpm is the rotational speed of the rotor in revolutions per minute.

To calculate the equivalent RCF of a 2 hour 100,000g spin on a 48,000g centrifuge, we can first calculate the RCF of the original spin using the given parameters:

RCF = 1.118 x 10^-5 x r x (rpm)^2 100,000g = 1.118 x 10^-5 x r x (rpm)^2

Assuming a rotor radius of 10 cm, we can solve for the rpm:

100,000g = 1.118 x 10^-5 x 10 x (rpm)^2 rpm^2 = 100,000g / (1.118 x 10^-5 x 10) rpm = 14,165

Therefore, the original spin was performed at 14,165 rpm.

Next, we can calculate the equivalent RCF for a 2 hour spin at 48,000g by solving for the rpm:

48,000g = 1.118 x 10^-5 x r x (rpm)^2

Assuming the same rotor radius of 10 cm, we can solve for the rpm:

48,000g = 1.118 x 10^-5 x 10 x (rpm)^2 rpm^2 = 48,000g / (1.118 x 10^-5 x 10) rpm = 8,196

Therefore, the equivalent of a 2 hour 100,000g spin on a 48,000g centrifuge would be a 2 hour spin at 8,196 rpm on a centrifuge with a rotor radius of 10 cm.