Assume that a circular platform is an ideal rigid body, it rotates around its center of circle with fixed angular velocity ω1. Given a particle 'p' on the platform, I have known its angular velocity ω1 . Keeping same angular velocity, I tilt the platform by an angle 'phi' respected x-y plane. The projection of particle motion path on the x-y plane will be a ellipse. May I calculate angular velocity ω2 of projection of particle on the x-y plane based on angular velocity ω1?
Thanks for your answer.
V = Vo(1-(1-COS(fi))cos(theta))
R = Ro(1-(1-COS(fi))sin(theta))
JES
OK,
fi is the angle of inclination while theta is the angle in the circle starting from the point where the planes intersect.
omega = V sin(alpha)/R where alpha is the angle between the tangent of the curve relative to the radius.
JES
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