If band structure is anisotropic in k-space, then how will the convergence of two bands normally appearing at two different symmetric point in the Brillouin zone will enhance See-back Coefficient?
Hello Sashi,
following Mott's equation, the Seebeck coefficient S is proportional to d (ln sigma) / dE at the Fermilevel. The conductivity sigma is the sum of the contribution of 2 bands (sigma = sigma1 + sigma 2), if the quasifermilevel cuts this two bands. The bandstructure determines the occupation and mobility of charge carriers within this bands. The mobilities (effective masses) are different in anisotropic substances. Therefore it can be, that the contribution of the second band is small.
Generally, you have two contributions to S depending on position of the fermi level and on the band curvuature (masses).-
With regards
R. Mitdank
Hello Sashi,
following Mott's equation, the Seebeck coefficient S is proportional to d (ln sigma) / dE at the Fermilevel. The conductivity sigma is the sum of the contribution of 2 bands (sigma = sigma1 + sigma 2), if the quasifermilevel cuts this two bands. The bandstructure determines the occupation and mobility of charge carriers within this bands. The mobilities (effective masses) are different in anisotropic substances. Therefore it can be, that the contribution of the second band is small.
Generally, you have two contributions to S depending on position of the fermi level and on the band curvuature (masses).-
With regards
R. Mitdank
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