In simulating a MSM photodetector, I want to see how does the fermi level of metal change when applying voltage to any of metals. The conduction and valence band energy level of metals does not change due to applying positive or negative biases, but the Electron QFL changes!
Is there anyone how knows what Electron QFL in metal means?
Does it means the level where the conductive electrons is there, as the conductive electron is in the last band energy of metals? As if it's true, why the conduction and valence band energy level of metal does not changes by applying voltage and the both metals which has been applied negative and which has been applied positive voltage, have the same level of conduction and valence band energy level?
Fermi level obeys to its definition: the Fermi level is a hypothetical energy level, which ensures 50% probability of being occupied by electron at any given time.
In some circumstances, when conduction and valence band energy level of metals does not change due to applying positive or negative biases, but the Electron QFL changes, suggest carrier concentration changing.
FYI we did in the past simulation of MSM photodetectors (AlGaN) using SILVACO but i'm not sure to understand your question, sorry.
In short, SILVACO was not as flexible as we wanted and we then decided to develop our own tool using FEMLAB (comsol multiphysics).
See this paper if interested:
https://www.researchgate.net/publication/231055140_Design_fabrication_and_physical_analysis_of_TiNAlN_deep_UV_photodiodes?ev=prf_pub
Article Design, fabrication and physical analysis of TiN/AlN deep UV...
- Badges
- Science topic
- Similar topics
- Physical Sciences
- Materials Science
- Materials
- Carbon Materials
- Graphite
- Graphene