If we keep in mind that R^{4}=R^{+}xS^{3}=R^{3}*RP^{1} where * means a direct product with a singularity at the zero point of a 3-dimensional Euclidean space in which the projective line is contracted to a point and take into account that the projective line RP^{1} is homeomorphic to the circle S^{1}, then from the point of view of a 3-dimensional observer 4-dimensional Euclidean space looks like a cone manifold R^{3}*S^{1}
Igor Bayak
I have written R^{4}=R^{+}xS^{3}, but this is incorrect because at the zero point of R^{+}, the sphere S^{3} shrinks to a point. So, it will be correct R^{4}=R^{+}*S^{3}=R^{3}*S{1}, where the asterisk indicates the Cartesian product with a singularity at the zero point.
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