I would like to know the reaction products of a redox reaction.
Details of the experiment: Sn metallic electrodes were electrochemically sodiated using metallic sodium to form an alloy NaxSny (A strong reducing agent). The sodiated electrodes were taken to an argon filled glove box and a mixture of 2-propanol and propylene carbonate (1:1) was poured on the NaxSny electrodes. Bubbles were formed indicating the reduction of 2-propanol to propane. I want to know what would happen to NaSn during this reaction.
Propanol (-OH) + NaxSny (reducing agent) --------- Propane (I guess) + H2 (bubbles) + (What will happen to NaSn) Will it be back to metallic Sn and Sodium?
P.S: I can perform various analysis to find out the composition of products. But what to expect?
Sodium is leached out of the alloy and it reacts with propanol to form sodium isopropoxide and H2 gas and will leave Sn metal behind. I'm assuming you have excess of isopropanol stoichiometrically which would result in the propoxide staying dissolved in solution.
If you remove the solvent and run XRD, you'll be able to confirm sodium isopropoxide and metallic Sn. It should be noted that sodium isopropoxide is hygroscopic and air sensitive.
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