Does this theorem correct??

Theorem: A bounded linear operator T: X to Y is weakly compact if and only if it does not preserve a copy of l_1

That is, T is not weakly compact iff there exists a closed subspace M isomorphic to l1 such that the restriction of T on M is isomorphism

*l1 is the space of all absolutely summable sequences

More Alice Alice's questions See All
Similar questions and discussions