I'm doing experiment on Sulphur dissolution in ionic liquid solvent. I need to find the sulphur solubility using Uv-vis. How can i measure the presence of S in the mixture?
Dear Sir. Concerning your issue about the regoin of the peak in UV-Vis spectrum of elemental Sulphur. The optical absorption spectra of the sulfur homocycles Sn (n = 6–10,12, 15, 20) in methanol or methylcyclohexane solution have been recorded in the region 200–360 nm using a conventional spectrophotometer as well as a diode-array spectrophotometer. Each compound shows a characteristic absorption curve. The extinction coefficients at 254 nm increase with increasing ring size, and the lowest‐energy absorption maximum shifts to the red with increasing number of atoms in the molecule. The data are used to re‐interprete the published absorption spectra of liquid and irradiated sulfur. I think the following below links may help you in your analysis:
https://onlinelibrary.wiley.com/doi/pdf/10.1002/bbpc.198800031
https://www.researchgate.net/publication/225814352_Molecular_Spectra_of_Sulfur_Molecules_and_Solid_Sulfur_Allotropes
http://www.electrochemsci.org/papers/vol7/7010561.pdf
Thanks
Sulphur has a peak that appears in the far UV. However, once Sulphur is oxidized to Sulphate anion it is commonly precipitated out of solution as Barium Sulphate by a solution of Barium Chloride. OR you can use a LECO CHNS analyzer (Carbon, Hydrogen, Nitrogen, Sulphur).
Ok, if we will go the way suggested by Bruce - for sulfur determination you can use also XRF - without any sample preparation.
Everything depends on the ILs composition. If there is no "S" you have bigger choice.
But, still you can use UV. The best region is 240-300 nm. Check this paper:
https://pubs.acs.org/doi/abs/10.1021/ac60071a047
This approach also dpends on the IL's spectrum/background. A standard addition method would be useful if you will have overlap of the UV absorbance of S and ILs.
regards,
G
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