I will like to graft trimethoxysilylpropyl 2-methylimidazole on silica. Normally, the trimethoxysilylpropyl group is linked to a N-atom of 2-methylimidazole. However, I will like to have a structure in which the Trimethoxysilylpropyl is link to carbon atom 4 of 2-methylimidazole (i.e. 4-trimethoxysilylpropyl-2-methylimidazole - refer to attached file). For my purpose, I need both N-atoms of 2-methylimidazole to be "free' and the methyl group between then is also vital. Is there a chemistry through which this can be achieved?
Thank you for your assistance.
Dear Joel,
You can purchase Trimethoxysilylpropyl Imidazole (PubChem CID: 14419323)
https://pubchem.ncbi.nlm.nih.gov/compound/14419323
And conduct C-methylation of the imidazol ring of trimethoxysilylpropyl Imidazole
Alternatively, you can use the commercially available trimethoxysilylpropyl Imidazole as it without methylation which might be good enough for your purposes (the two nitrogens of the imidazole ring are naked).
Hoping this will be helpful,
Rafik
Dear Rafik
Thank you for your contribution. As pointed out by Micheal, it appears Trimethoxysilylpropyl Imidazole (PubChem CID: 14419323) can not be purchased. Regarding your proposed plan B, I have modified my question to read as such " ... For my purpose, I need both N-atoms of 2-methylimidazole to be "free' and the methyl group between then is also vital" ..
The mild electron donating effect of the methyl group between the two N-toms plays an important role in my application.
Thank you once more for your time and contribution.
Dear Micheal
Thank you very much for the suggested article. After going through the paper, I think it is definitely an option worth considering. I am looking at the possibility of putting it in use.
Thank you once more
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