The throughput of a channel is a measure of amount of data actually moves through the channel. Why is it substantially less than the bandwidth of the channel?
- According to Shannon, the theoretical maximum capacity C of a channel can be estimated by: C = BW x log2(1+S/N) [bps], where BW is the bandwidth, S/N is the signal to noise ratio (SNR).
One can conclude that the lower the SNR the lower the channel capacity.
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