Not sure I quite understand your question, so bear with me as I attempt an answer. Different species' eyes are fitted with different arrays of so-called cones and rods. The cones are responsible for color perception - color cannot be perceived directly by any eye, because color stems from wavelength and there is no way to measure wavelength directly: only photon energies can be apprehended and measured by chemicals - such as the chemicals in the eye.

Animals with only one kind of cones - such as dogs - can therefore only see in black and grey and white.

Animals with three kinds of cones, such as humans, with each type of cone being made up of separate chemicals which resonate within different , narrow photon energy ranges - thus enable their brains to artificially reconstitute colors: if, for instance, photon absorption occurred primarily with the cones resonant with low photon energy, then the brain interprets this as a red color.

Some bird species have four cones, which enables them to see near UV and/or near IR colors (which is why we perceive some female birds as dull, whereas the male of their species perceive them as highly colorful)

Now if the chemicals within the cones are not tuned to resonance for a certain narrow range of the electromagnetic spectrum (answering to certain photon energies), then all the photons of that particular range will not be absorbed by the cones and hence will not be seen by the eye. This is why humans do not see UV or IR, let alone gamma rays or radio waves.

X and gamma rays have typical a much higher energy than the binding energies of all or at least most of the electrons in the target. As a consequence the interaction probability just drops down with increasing photon energy.

However, for photons in the energy region of a few eV the photons are near the binding energy of the valence electrons. In this regime you have a non-trivial interaction probability which may rise/drop sharpy if your photon energy scans over an atomic/molecular transition (resonance phenomena).

If you now reduce your photon energy further, your photons will no longer have sufficient energy to excite these transitions. As a consequence, your interaction probability drops again. But please be aware of the fact, that the latter strongly depends on the atomic/chemical properties of your sample.

Photon (x or gamma rays ) can interacts with matter through three main mechanism

1. Photoelectric effect 2. Compton effect 3. Pair production

photoelectric effect will occur at lower photon energies, in which photon gives all its energy to orbital electron therefore, energy loss of photon is more significant for lower energy therefore penetration of lower energy photon is low.

As energy increases, the Compton effect plays major role of interaction in which photon do not gives all its energy to electron but it scatters through a certain angle by loosing fraction of its energy to electron. therefore high photon can travel more distance in matter than the low energy photon. It means as energy of photon increases its penetration power will also increases...

I hope you will get your answer.....

I agree with the previous answers and would just like to add a few comments on the energy dependence of the photoelectric effect for X-rays and gamma rays (i.e., energies in the keV range and up).

As already described, the photoelectric effect decreases fast with the photon energy (approximately as 1 / energy^3.5). This is because of momentum conservation (momentum = mass * velocity) and energy conservation:

momentum of incoming photon = momentum of emitted electron + momentum of the ion

energy of incoming photon = energy of emitted electron - binding energy of electron

If the energy of the incoming photon is high, then the energy of the emitted electron is also high. But because an electron is more massive than a photon, it turns out that the momentum of the emitted electron must be much higher than the momentum of the incoming photon, leaving the ion with negative (backward) momentum.

This means that the electron must be "cought" by the photon at a moment when it already has high forward momentum. Due to quantum mechanings, the electron can have momentum at any value, but the high values are improbably.

So: High energy of incoming photon => ejected electron must have high momentum (otherwise energy conservation will not match up) => bound electron must be hit at a time when it already has high momentum in the direction of the photon. The higher momentom involved, the less likely is the interaction.

Thus, high incoming photon energy => low probability of photoelectric absorption.

Hope this is useful. As stressed in a previous answer, the situation is much more complicated in the UV range.